H=3t^2-15t

Solution for H=3t^2-15t equation:

=3H^2-15H

We move all terms to the left:

-(3H^2-15H)=0

We get rid of parentheses

-3H^2+15H=0

a = -3; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-3)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-3}=\frac{-30}{-6}
=+5
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-3}=\frac{0}{-6}
=0
$